# A force of 5 pounds stretches

A force of 5 pounds stretches a spring 1 foot. A mass weighing 6.4 pounds is attached to the spring, and the system is then immersed in a medium that offers a damping force numerically equal to 1.6 times the instantaneous velocity.

I calculated that the equation of motion if the mass is initially released from rest from a point 1 foot above the equilibrium position is : x(t) = e^(-4t) [-cos(3t) – 4/3sin(3t)]

### Save your time - order a paper!

Get your paper written from scratch within the tight deadline. Our service is a reliable solution to all your troubles. Place an order on any task and we will take care of it. You won’t have to worry about the quality and deadlines

Order Paper Now

Please help me find the equation of motion in the form x(t) = Ae^(??t) sin(sqrt(?^2 – ?^2) + )

-When i tried getting this i got A =4/3, w^2 = 25, lambda = 16, pheta = arctan(3/4)

Find the first time at which the mass passes through the equilibrium position heading upward

_________________S

Please help me find the equation of motion in the form x(t) = Ae^(??t) sin(sqrt(?^2 – ?^2) + )

x(t) = _____________________

[promo2]